10x^2+25x-60=0

Solution for 10x^2+25x-60=0 equation:

10x^2+25x-60=0

a = 10; b = 25; c = -60;
Δ = b2-4ac
Δ = 252-4·10·(-60)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-55}{2*10}=\frac{-80}{20}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+55}{2*10}=\frac{30}{20}
=1+1/2
$